Let $E_1(r), E_2(r)$ and $E_3(r)$ be the respective electric fields at a distance $r$ from a point charge $Q$, an infinitely long wire with constant linear charge density $\lambda$, and an infinite plane with uniform surface charge density $\sigma$. if $E_1\left(r_0\right)=E_2\left(r_0\right)=E_3\left(r_0\right)$ at a given distance $r_0$, then
$Q =4 \sigma \pi r_0^2$
$r_0=\frac{\lambda}{2 \pi \sigma}$
$E_1\left(r_0 / 2\right)=2 E_2\left(r_0 / 2\right)$
$E_2\left(r_0 / 2\right)=4 E_3\left(r_0 / 2\right)$
There is a solid sphere of radius $‘R’$ having uniformly distributed charge throughout it. What is the relation between electric field $‘E’$ and distance $‘r’$ from the centre ( $r$ is less than R ) ?
The dimensions of an atom are of the order of an Angstrom. Thus there must be large electric fields between the protons and electrons. Why, then is the electrostatic field inside a conductor zero ?
Electric field at a point varies as ${r^o}$ for
A hollow metal sphere of radius $R$ is uniformly charged. The electric field due to the sphere at a distance r from the centre
Let $\rho (r)\, = \frac{Q}{{\pi {R^4}}}\,r$ be the volume charge density distribution for a solid sphere of radius $R$ and total charge $Q$. For a point $'p'$ inside the sphere at distance $r_1$ from the centre of the sphere, the magnitude of electric field is