Gujarati
1. Electric Charges and Fields
medium

Consider a uniform spherical charge distribution of radius $R_1$ centred at the origin $O$. In this distribution, a spherical cavity of radius $R_2$, centred at $P$ with distance $O P=a=R_1-R_2$ (see figure) is made. If the electric field inside the cavity at position $\overrightarrow{ r }$ is $\overrightarrow{ E }(\overrightarrow{ r })$, then the correct statement$(s)$ is(are) $Image$

A

$\vec{E}$ is uniform, its magnitude is independent of $R_2$ but its direction depends on $\vec{r}$

B

$\vec{E}$ is uniform, its magnitude depends on $R_2$ and its direction depends on $\overrightarrow{ r }$

C

$\overrightarrow{ E }$ is uniform, its magnitude is independent of $a$ but its direction depends on a $\vec{a}$

D

$\overrightarrow{ E }$ is uniform and both its magnitude and direction depend on $\overrightarrow{ a }$

(IIT-2015)

Solution

$\overrightarrow{ E }=\frac{\rho}{3 \varepsilon_0} \overline{ C _1 C _2}$

$C _1 \Rightarrow$ centre of sphere and $C _2 \Rightarrow$ centre of cavity.

Standard 12
Physics

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