Let R be a relation from A = {2,3,4,5} to B = {3,6,7,10} defined by R = {(a,b) | a divides b, a ∈&

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1.Relation and Function

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Let $R$ be a relation from $A = \{2,3,4,5\}$ to $B = \{3,6,7,10\}$ defined by $R = \{(a,b) |$ $a$ divides $b, a \in A, b \in B\}$, then number of elements in $R^{-1}$ will be-

A

$0$

B

$3$

C

$4$

D

$5$

Solution

$R = {(2,6), (2,10), (3,3), (3,6),(5,10)}$
$\therefore 5$ elements in $R^{-1}$

Standard 12

Mathematics

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