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1.Relation and Function
normal
Let $R$ be a relation from $A = \{2,3,4,5\}$ to $B = \{3,6,7,10\}$ defined by $R = \{(a,b) |$ $a$ divides $b, a \in A, b \in B\}$, then number of elements in $R^{-1}$ will be-
A
$0$
B
$3$
C
$4$
D
$5$
Solution
$R = {(2,6), (2,10), (3,3), (3,6),(5,10)}$
$\therefore 5$ elements in $R^{-1}$
Standard 12
Mathematics