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10-2. Parabola, Ellipse, Hyperbola
normal
Let $P(2,2)$ be a point on an ellipse whose foci are $(5,2)$ and $(2,6)$, then eccentricity of ellipse is
A
$\frac{2}{3}$
B
$\frac{5}{7}$
C
$\frac{1}{3}$
D
$\frac{3}{4}$
Solution
$\mathrm{PF}_{1}+\mathrm{PF}_{2}=7=2 \mathrm{a}$
$\mathrm{F}_{1} \mathrm{F}_{2}=5=2 \mathrm{ae}$
$\therefore e=\frac{5}{7}$
Standard 11
Mathematics