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4-1.Complex numbers
normal
Let complex number $z$ be such that $|z- \frac{6}{z}|=5$ then maximum value of $|z|$ will be -
A
$2$
B
$3$
C
$5$
D
$6$
Solution
$\left|z-\frac{6}{z}\right| \geq|z|-\frac{6}{|z|} \Rightarrow 5 \geq|z|-\frac{6}{|z|}$
$\Rightarrow|z|^{2}-5|z|-6 \leq 0$
$\Rightarrow|z| \in[-1,6]$
$\therefore$ maximum value $=6$
Standard 11
Mathematics