Let the ellipse, $E _1: \frac{ x ^2}{ a ^2}+\frac{ y ^2}{b^2}=1, a > b$ and $E _2: \frac{ x ^2}{A^2}+\frac{ y ^2}{B^2}=1, A< B$ have same eccentricity $\frac{1}{\sqrt{3}}$. Let the product of their lengths of latus rectums be $\frac{32}{\sqrt{3}}$, and the distance between the foci of $E_1$ be $4$. If $E_1$ and $E_2$ meet at $A, B, C$ and $D$, then the area of the quadrilateral $A B C D$ equals:

  • [JEE MAIN 2025]
  • A
    $6 \sqrt{6}$
  • B
    $\frac{18 \sqrt{6}}{5}$
  • C
    $\frac{12 \sqrt{6}}{5}$
  • D
    $\frac{24 \sqrt{6}}{5}$

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