Let the equation $x^{2}+y^{2}+p x+(1-p) y+5=0$ represent circles of varying radius $\mathrm{r} \in(0,5]$. Then the number of elements in the set $S=\left\{q: q=p^{2}\right.$ and $\mathrm{q}$ is an integer $\}$ is ..... .

  • [JEE MAIN 2021]
  • A

    $60$

  • B

    $61$

  • C

    $62$

  • D

    $63$

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$x^2 + y^2 -2x + 4y -4 = 0$ and
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The circle on the chord $x\cos \alpha + y\sin \alpha = p$ of the circle ${x^2} + {y^2} = {a^2}$ as diameter has the equation