Match List $I$ with List $II$ and select the correct answer using the codes given below the lists :
List $I$
List $II$
$P.$ Boltzmann constant
$1.$ $\left[ ML ^2 T ^{-1}\right]$
$Q.$ Coefficient of viscosity
$2.$ $\left[ ML ^{-1} T ^{-1}\right]$
$R.$ Planck constant
$3.$ $\left[ MLT ^{-3} K ^{-1}\right]$
$S.$ Thermal conductivity
$4.$ $\left[ ML ^2 T ^{-2} K ^{-1}\right]$
Codes: $ \quad \quad P \quad Q \quad R \quad S $
Match List $I$ with List $II$ and select the correct answer using the codes given below the lists :
| List $I$ | List $II$ |
| $P.$ Boltzmann constant | $1.$ $\left[ ML ^2 T ^{-1}\right]$ |
| $Q.$ Coefficient of viscosity | $2.$ $\left[ ML ^{-1} T ^{-1}\right]$ |
| $R.$ Planck constant | $3.$ $\left[ MLT ^{-3} K ^{-1}\right]$ |
| $S.$ Thermal conductivity | $4.$ $\left[ ML ^2 T ^{-2} K ^{-1}\right]$ |
Codes: $ \quad \quad P \quad Q \quad R \quad S $
- [IIT 2013]
- A
$\quad 3 \quad 1 \quad 2 \quad 4 $
- B
$\quad 3 \quad 2 \quad 1 \quad 4 $
- C
$\quad 4 \quad 2 \quad 1 \quad 3 $
- D
$\quad 4 \quad 1 \quad 2 \quad 3 $
Similar Questions
Dimensional formula $M{L^{ - 1}}{T^{ - 2}}$ does not represent the physical quantity
Dimensional formula $M{L^{ - 1}}{T^{ - 2}}$ does not represent the physical quantity
Identify the pair whose dimensions are equal
Identify the pair whose dimensions are equal
- [AIEEE 2002]
Match List $-I$ with List $-II$
List $-I$
List $-II$
$A$.
Coefficient of Viscosity
$I$.
$[M L^2T^{–2}]$
$B$.
Surface Tension
$II$.
$[M L^2T^{–1}]$
$C$.
Angular momentum
$III$.
$[M L^{-1}T^{–1}]$
$D$.
Rotational Kimeatic energy
$IV$.
$[M L^0T^{–2}]$
Match List $-I$ with List $-II$
| List $-I$ | List $-II$ | ||
| $A$. | Coefficient of Viscosity | $I$. | $[M L^2T^{–2}]$ |
| $B$. | Surface Tension | $II$. | $[M L^2T^{–1}]$ |
| $C$. | Angular momentum | $III$. | $[M L^{-1}T^{–1}]$ |
| $D$. | Rotational Kimeatic energy | $IV$. | $[M L^0T^{–2}]$ |
- [JEE MAIN 2024]
Dimension of electric current is
Dimension of electric current is
The equation of state of some gases can be expressed as $\left( {P + \frac{a}{{{V^2}}}} \right)\,(V - b) = RT$. Here $P$ is the pressure, $V$ is the volume, $T$ is the absolute temperature and $a,\,b,\,R$ are constants. The dimensions of $'a'$ are
The equation of state of some gases can be expressed as $\left( {P + \frac{a}{{{V^2}}}} \right)\,(V - b) = RT$. Here $P$ is the pressure, $V$ is the volume, $T$ is the absolute temperature and $a,\,b,\,R$ are constants. The dimensions of $'a'$ are