The force is given in terms of time t and dis | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$	heta$ of cos or sin should be dimensionless.
${[ A ]=\left[ MLT ^{-2}ight] }$
${[ B ]=\left[ L ^{-1}ight] }$
${[ D ]=\left[ T ^{-1}ight] }

Vedclass · Accepted Answer

$\left[{ML}^{2} {T}^{-3}\right]$

Vedclass · Answer

$	heta$ of cos or sin should be dimensionless.
${[ A ]=\left[ MLT ^{-2}ight] }$
${[ B ]=\left[ L ^{-1}ight] }$
${[ D ]=\left[ T ^{-1}ight] }$
${\left[\frac{ AD }{ B }ight]=\frac{\left[ MLT ^{-2}ight]\left[ T ^{-1}ight]}{\left[ L ^{-1}ight]} }$
${\left[\frac{ AD }{ B }ight]=\left[ ML ^{2} T ^{-3}ight] }$

The force is given in terms of time $t$ and displacement $x$ by the equation
${F}={A} \cos {Bx}+{C} \sin {Dt}$
The dimensional formula of $\frac{{AD}}{{B}}$ is -

Similar Questions

In the equation $\left[X+\frac{a}{Y^2}\right][Y-b]= R T, X$ is pressure, $Y$ is volume, $R$ is universal gas constant and $T$ is temperature. The physical quantity equivalent to the ratio $\frac{a}{b}$ is

If ${E}, {L}, {m}$ and ${G}$ denote the quantities as energy, angular momentum, mass and constant of gravitation respectively, then the dimensions of ${P}$ in the formula ${P}={EL}^{2} {m}^{-5} {G}^{-2}$ are

If the present units of length. time and mass $(m, s, k g)$ are changed to $100\; m, 100\; s$. $\frac{1}{10} \;k g$ then

Frequency is the function of density $(\rho )$, length $(a)$ and surface tension $(T)$. Then its value is

$1$ $joule$ of energy is to be converted into new system of units in which length is measured in $10\, m$, mass in $10\, kg$ and time in $1$ $minute$ then numerical value of $1\, J$ in the new system is

The force is given in terms of time $t$ and displacement $x$ by the equation ${F}={A} \cos {Bx}+{C} \sin {Dt}$ The dimensional formula of $\frac{{AD}}{{B}}$ is -