Minimum distance between two points $P$ and $Q$ on the ellipse $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{4} = 1$ , if difference between eccentric angles of $P$ and $Q$ is $\frac{{3\pi }}{2}$ , is

  • A

    $2\sqrt 2 $

  • B

    $2\sqrt 5 $

  • C

    $\sqrt {29} $

  • D

    $\sqrt {62} $

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