Number of positive integral values of 'K& | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\left| {x + \left| {2x - 1} \right|} \right| - \left| {x - \left| {2x - 1} \right|} \right| = 2Min\left( {x,\left| {2x - 1} \right|} \right)$

$|2

Vedclass · Accepted Answer

$0$

Vedclass · Answer

$\left| {x + \left| {2x - 1} ight|} ight| - \left| {x - \left| {2x - 1} ight|} ight| = 2Min\left( {x,\left| {2x - 1} ight|} ight)$

$|2 x-1|=x$

$	herefore 2 x-1=\pm x$

$x=1, \frac{1}{3}$

at $x=\frac{1}{3}$

$\mathrm{k}=\left|\frac{1}{3}+\frac{1}{3}ight|=\frac{2}{3}$

Number of positive integral values of $'K'$ for which the equation $k = \left| {x + \left| {2x - 1} \right|} \right| - \left| {x - \left| {2x - 1} \right|} \right|$ has exactly three real solutions, is

Similar Questions

If $x$ is real and $k = \frac{{{x^2} - x + 1}}{{{x^2} + x + 1}},$ then

If $|{x^2} - x - 6| = x + 2$, then the values of $x$ are

In the real number system, the equation $\sqrt{x+3-4 \sqrt{x-1}}+\sqrt{x+8-6 \sqrt{x-1}}=1$ has

The number of real roots of the equation $x | x |-5| x +2|+6=0$, is

If ${x^2} + 2ax + 10 - 3a > 0$ for all $x \in R$, then