Trigonometrical Equations
normal

સમીકરણ $sgn(sin x) = sin^2x + 2sinx + sgn(sin^2x)$  ના  $\left[ { - \frac{{5\pi }}{2},\frac{{7\pi }}{2}} \right]$ માં ઉકેલોની સંખ્યા મેળવો,

(જ્યાં $sgn(.)$ એ ચિહન વિધેય છે) 

A

$10$

B

$6$

C

$13$

D

$9$

Solution

One solution will be $sinx = 0$ $ x = 0, ± \pi , ± 2\pi , 3\pi $ and if $sinx \neq  0$, then equation become $(sinx + 1)^2 = ± 1$ valid only at $sinx = 0$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.