Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

Objects $A$ and $B$ each of mass $m$ are connected by light inextensible cord. They are constrained to move on a frictionless ring in a vertical plane as shown in figure. The objects are released from rest at the positions shown. The tension in the cord just after release will be

A

$\frac{ mg }{\sqrt{2}}$

B

$mg \sqrt{2}$

C

$\frac{ mg }{2}$

D

$\frac{ mg }{4}$

Solution

Force along the rod is same

$=m g \cos 45^{\circ}=\frac{ mg }{\sqrt{2}}$

Standard 11
Physics

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