Obtain equation of electric energy of a single charge.

Vedclass pdf generator app on play store
Vedclass iOS app on app store

The external electric field $\overrightarrow{\mathrm{E}}$ and the corresponding external potential $\mathrm{V}$ may vary from point to point.

According to definition of electric potential $V$ at a point $P$ is the work done in bringing a unit positive charge from infinity to the point $\mathrm{P}$. (We assume the potential at infinity to be zero.) Thus, work done in bringing a charge $q$ from infinity to the point $P$ in the external field is $\mathrm{W}=q \mathrm{~V}$.

This work is stored in the form of potential energy of $q$,

$\therefore \mathrm{U}=q \mathrm{~V}$

If the point $\mathrm{P}$ has position vector $\vec{r}$ relative to origin, then potential energy at point $\mathrm{P}$, $\mathrm{U}(\vec{r})=q \mathrm{~V}(\vec{r})$

Means potential energy in an external field = electric charge $\times$ electric potential in external field.

Similar Questions

A particle of charge $q$ and mass $m$ is subjected to an electric field $E = E _{0}\left(1- ax ^{2}\right)$ in the $x-$direction, where $a$ and $E _{0}$ are constants. Initially the particle was at rest at $x=0 .$ Other than the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is

  • [JEE MAIN 2020]

A uniformly charged ring of radius $3a$ and total charge $q$ is placed in $xy-$ plane centered at origin. A point charge $q$ is moving towards the ring along the $z-$ axis and has speed $v$ at $z = 4a$. The minimum value of $v$ such that it crosses the origin is

  • [JEE MAIN 2019]

A point charge $q$ of mass $m$ is suspended vertically by a string of length $l$. A point dipole of dipole moment $\overrightarrow{ p }$ is now brought towards $q$ from infinity so that the charge moves away. The final equilibrium position of the system including the direction of the dipole, the angles and distances is shown in the figure below. If the work done in bringing the dipole to this position is $N \times( mgh )$, where $g$ is the acceleration due to gravity, then the value of $N$ is. . . . . . (Note that for three coplanar forces keeping a point mass in equilibrium, $\frac{F}{\sin \theta}$ is the same for all forces, where $F$ is any one of the forces and $\theta$ is the angle between the other two forces)

  • [IIT 2020]

An electron (charge = $1.6 \times {10^{ - 19}}$ $coulomb$) is accelerated through a potential of $1,00,000$ $volts$. The energy required by the electron is

Two charges $-q$ and $+q$ are located at points $(0,0,-a)$ and $(0,0, a)$ respectively.

$(a)$ What is the electrostatic potential at the points $(0,0, z)$ and $(x, y, 0) ?$

$(b)$ Obtain the dependence of potential on the distance $r$ of a point from the origin when $r / a\,>\,>\,1$

$(c)$ How much work is done in moving a small test charge from the point $(5,0,0)$ to $(-7,0,0)$ along the $x$ -axis? Does the answer change if the path of the test charge between the same points is not along the $x$ -axis?