Obtain the equation of speed of transverse wave on tensed (stretched) string.
The speed of transverse waves on a string is determined by two factors, $(i)$ the linear mass density or mass per unit length $\mu$ and $(ii)$ the tension $\mathrm{T}$.
The linear mass density, $\mu$ of a string is the mass $m$ of the string divided by its length $l$. Therefore its dimension is $\left[\mathrm{M}^{1} \mathrm{~L}^{-1}\right]$. The tension $\mathrm{T}$ has the dimension of force - namely $\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}\right] .$
We have to combine $\mu$ and $\mathrm{T}$ in such a way as to generate $v$ [dimension (LT $^{-1}$ )].
It can be seen that the ratio $\frac{T}{\mu}$ has the dimension $\left[\mathrm{L}^{2} \mathrm{~T}^{-2}\right]$.
$\left[\frac{T}{\mu}\right]=\frac{\left[M^{1} L^{1} T^{-2}\right]}{\left[M^{1} L^{-1}\right]}=\left[L^{2} T^{-2}\right]$
Therefore, if $v$ depends only on $\mathrm{T}$ and $\mu$, the relation between them must be,
$v=C \sqrt{\frac{T}{\mu}}$
Here $\mathrm{C}$ is a dimensionless constant and constant $\mathrm{C}$ is indeed equal to unity.
The speed of transverse waves on a stretched string is therefore given by,
$v=\sqrt{\frac{\mathrm{T}}{\mu}}$
A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, $y(x$, $t )=(0.01 \ m ) \sin \left[\left(62.8 \ m ^{-1}\right) x \right] \cos \left[\left(628 s ^{-1}\right) t \right]$. Assuming $\pi=3.14$, the correct statement$(s)$ is (are) :
$(A)$ The number of nodes is $5$ .
$(B)$ The length of the string is $0.25 \ m$.
$(C)$ The maximum displacement of the midpoint of the string its equilibrium position is $0.01 \ m$.
$(D)$ The fundamental frequency is $100 \ Hz$.
The extension in a string, obeying Hooke's law, is $x$. The speed of sound in the stretched string is $v$. If the extension in the string is increased to $1.5x$, the speed of sound will be
A wire of density $9 \times 10^{-3} \,kg\, cm ^{-3}$ is stretched between two clamps $1\, m$ apart. The resulting strain in the wire is $4.9 \times 10^{-4}$. The lowest frequency of the transverse vibrations in the wire is......$HZ$
(Young's modulus of wire $Y =9 \times 10^{10}\, Nm ^{-2}$ ), (to the nearest integer),
Speed of a transverse wave on a straight wire (mass $6.0\; \mathrm{g}$, length $60\; \mathrm{cm}$ and area of cross-section $1.0\; \mathrm{mm}^{2}$ ) is $90\; \mathrm{ms}^{-1} .$ If the Young's modulus of wire is $16 \times 10^{11}\; \mathrm{Nm}^{-2},$ the extension of wire over its natural length is
A pulse is generated at lower end of a hanging rope of uniform density and length $L$. The speed of the pulse when it reaches the mid point of rope is ......