- Home
- Standard 11
- Mathematics
Of the members of three athletic teams in a school $21$ are in the cricket team, $26$ are in the hockey team and $29$ are in the football team. Among them, $14$ play hockey and cricket, $15$ play hockey and football, and $12$ play football and cricket. Eight play all the three games. The total number of members in the three athletic teams is
$43$
$76$
$49$
None of these
Solution
(a) Let $B, H, F$ denote the sets of members who are on the basketball team, hockey team and football team respectively.
Then we are given $n\,(B) = 21,\,n\,(H) = 26,n\,(F) = 29$
$n\,(H \cap B) = 14$, $n\,(H \cap F) = 15$, $n\,(F \cap B) = 12$
and $n\,(B \cap H \cap F) = 8$.
We have to find $n\,(B \cup H \cup F)$.
To find this, we use the formula
$n\,(B \cup H \cup F) = n\,(B) + n\,(H) + n\,(F)$
$ – n\,(B \cap H) – n\,(H \cap F) – n\,(F \cap B) + n\,(B \cap H \cap F)$
Hence,$n\,(B \cup H \cup F) = (21 + 26 + 29) – (14 + 15 + 12) + 8 = 43$
Thus these are $43$ members in all.
