8.Mechanical Properties of Solids
medium

On applying a stress of $20 \times {10^8}N/{m^2}$ the length of a perfectly elastic wire is doubled. Its Young’s modulus will be

A

$40 \times {10^8}N/{m^2}$

B

$20 \times {10^8}N/{m^2}$

C

$10 \times {10^8}N/{m^2}$

D

$5 \times {10^8}N/{m^2}$

Solution

(b) Young’s modules =$\frac{{{\rm{stress}}}}{{{\rm{strain}}}}$

As the length of wire get doubled therefore strain $= 1$

$Y =$ strain $= 20 \times 10^8 N/ m^2$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.