Gujarati
Hindi
6.System of Particles and Rotational Motion
easy

To maintain a rotor at a uniform angular speed of $100\, rad\, s^{-1}$, an engine needs to transmit torque of $100\, Nm$. The power of the engine is

A

$10\,kW$

B

$100\,kW$

C

$10\,mW$

D

$100\,mW$

Solution

Power of the engine $\mathrm{p}=\tau \omega$

$\therefore$     $\mathrm{p}=(100 \mathrm{Nm})\left(100 \mathrm{rad} \mathrm{s}^{-1}\right)$

$=10 \mathrm{kW}$

Standard 11
Physics

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