One side of a square is inclined at an acute angle $\alpha$ with the positive $x-$axis, and one of its extremities is at the origin. If the remaining three vertices of the square lie above the $x-$axis and the side of a square is $4$, then the equation of the diagonal of the square which is not passing through the origin is
One side of a square is inclined at an acute angle $\alpha$ with the positive $x-$axis, and one of its extremities is at the origin. If the remaining three vertices of the square lie above the $x-$axis and the side of a square is $4$, then the equation of the diagonal of the square which is not passing through the origin is
- A
$(cos\, \alpha + sin\, \alpha) x + (cos\, \alpha - sin\, \alpha) y = 4$
- B
$(cos\, \alpha + sin\, \alpha) x - (cos\, \alpha - sin\, \alpha) y = 4$
- C
$(cos\, \alpha - sin\, \alpha) x + (cos\, \alpha + sin\, \alpha) y = 4$
- D
$(cos\, \alpha - sin\, \alpha) x - (cos\, \alpha + sin\, \alpha) y = 4 cos\, 2\alpha$
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