Out of three numbers, first is twice second and is half of third. If average of three numbers is 56,

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Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is $56,$ the three numbers in order are

A

$48,96,24$

B

$48,24,96$

C

$96,24,48$

D

$96,48,24$

Solution

Let, the numbers be $2 x, x$ and $4 x$.

Average $=\frac{2 x+x+4 x}{3} \Rightarrow \frac{7 x}{3}=56$

$\therefore \quad x=\frac{3 \times 56}{7}=24$

Hence, the numbers in order are $48,\,24$ and $96 .$

Standard 13

Quantitative Aptitude

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