Planet $M$ orbits around its sun, $S$, in an elliptical orbit with the sun at one of the foci. When $M$ is closest to $S$, it is $2\,unit$ away. When $M$ is farthest from $S$, it is $18\, unit$ away, then the equation of motion of planet $M$ around its sun $S$, assuming $S$ at the centre of the coordinate plane and the other focus lie on negative $y-$ axis, is
$\frac{{{x^2}}}{{36}} + \frac{{{{\left( {y - 8} \right)}^2}}}{{100}} = 1$
$\frac{{{x^2}}}{{36}} + \frac{{{{\left( {y + 8} \right)}^2}}}{{100}} = 1$
$\frac{{{x^2}}}{{64}} + \frac{{{{\left( {y - 8} \right)}^2}}}{{100}} = 1$
$\frac{{{x^2}}}{{64}} + \frac{{{{\left( {y + 8} \right)}^2}}}{{100}} = 1$
The number of values of $c$ such that the straight line $y = 4x + c$ touches the curve $\frac{{{x^2}}}{4} + {y^2} = 1$ is
The equation of an ellipse whose focus $(-1, 1)$, whose directrix is $x - y + 3 = 0$ and whose eccentricity is $\frac{1}{2}$, is given by
If the eccentricity of an ellipse be $1/\sqrt 2 $, then its latus rectum is equal to its
In an ellipse, the distance between its foci is $6$ and minor axis is $8$. Then its eccentricity is
Area (in sq. units) of the region outside $\frac{|\mathrm{x}|}{2}+\frac{|\mathrm{y}|}{3}=1$ and inside the ellipse $\frac{\mathrm{x}^{2}}{4}+\frac{\mathrm{y}^{2}}{9}=1$ is