Planet $M$ orbits around its sun, $S$, in an elliptical orbit with the sun at one of the foci. When $M$ is closest to $S$, it is $2\,unit$ away. When $M$ is farthest from $S$, it is $18\, unit$ away, then the equation of motion of planet $M$ around its sun $S$, assuming $S$ at the centre of the coordinate plane and the other focus lie on negative $y-$ axis, is
$\frac{{{x^2}}}{{36}} + \frac{{{{\left( {y - 8} \right)}^2}}}{{100}} = 1$
$\frac{{{x^2}}}{{36}} + \frac{{{{\left( {y + 8} \right)}^2}}}{{100}} = 1$
$\frac{{{x^2}}}{{64}} + \frac{{{{\left( {y - 8} \right)}^2}}}{{100}} = 1$
$\frac{{{x^2}}}{{64}} + \frac{{{{\left( {y + 8} \right)}^2}}}{{100}} = 1$
A rod $AB$ of length $15\,cm$ rests in between two coordinate axes in such a way that the end point A lies on $x-$ axis and end point $B$ lies on $y-$ axis. A point $P(x,\, y)$ is taken on the rod in such a way that $AP =6\, cm .$ Show that the locus of $P$ is an ellipse.
If the distance between the foci of an ellipse be equal to its minor axis, then its eccentricity is
The equation of the ellipse whose latus rectum is $8$ and whose eccentricity is $\frac{1}{{\sqrt 2 }}$, referred to the principal axes of coordinates, is
The minimum area of a triangle formed by any tangent to the ellipse $\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{{81}} = 1$ and the coordinate axes is
The equation of the ellipse referred to its axes as the axes of coordinates with latus rectum of length $4$ and distance between foci $4 \sqrt 2$ is-