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5.Magnetism and Matter
easy
Points $A$ and $B$ are situated perpendicular to the axis of a small bar magnet at large distances $x$ and $3 x$ from its centre on opposite sides. The ratio of the magnetic fields at $A$ and $B$ will be approximately equal to
A
$2: 9$
B
$1: 9$
C
$27: 1$
D
$9: 1$
Solution
(c)
$B_A=\frac{\mu_0}{4 \pi} \frac{2 M}{x^3}$
$B_B=\frac{\mu_0}{4 \pi} \frac{2 M}{(3 x)^3}$
$\frac{B_A}{B_B}=\frac{1}{27}$
Standard 12
Physics
