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5.Magnetism and Matter
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Points $A$ and $B$ are situated perpendicular to the axis of a $2\,cm$ long bar magnet at large distances $X$ and $3X$ from its centre on opposite sides. The ratio of the magnetic fields at $ A$ and $B$ will be approximately equal to
A
$1:9$
B
$2:9$
C
$27:1$
D
$9:1$
Solution
(c)$B \propto \frac{1}{{{x^3}}} \Rightarrow \frac{{{B_1}}}{{{B_2}}} = {\left( {\frac{{{x_2}}}{{{x_1}}}} \right)^3} = {\left( {\frac{{3x}}{x}} \right)^3} = \frac{{27}}{1}$
Standard 12
Physics
