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Position time graph of a particle moving along straight line is shown which is in the form of semicircle starting from $t=2$ to $t=8 \,s$. Select correct statement
Velocity of particle between $t=0$ to $t=2 \,s$ is positive
Velocity of particle is opposite to acceleration between $t=2$ to $t=5 \,s$
Velocity of particle is opposite to acceleration between $t=5$ to $t=8 \,s$
Acceleration of particle is positive between $t_1=2 s$ to $t_2=5 \,s$ while it is negative between $t_1=5 \,s$ to $t_2=8 \,s$
Solution
(b)
$(i)$ From $0$ to $2 \,s$ the velocity $=0$ as displacement is zero.
$(ii)$ From $2$ to $5 \,s$ velocity is decreasing but nature is positive, but acceleration is negative.
So, $v$ and $a$ have opposite nature.
Similar Questions
Refer to the graph in figure. Match the following
| Graph | Characteristics |
| $(A)$ | $(i)$ has $v > 0$ and $a < 0$ throughout |
| $(B)$ | $(ii)$ has $x > 0,$ throughout and has a point with $v = 0$ and a point with $a = 0$ |
| $(C)$ | $(iii)$ has a point with zero displacement for $t > 0$ |
| $(D)$ | $(iv)$ has $v < 0$ and $a > 0$ |
