- Home
- Standard 11
- Physics
7.Gravitation
medium
Potential energy of a satellite having mass $‘m’$ and rotating at a height of $6.4 \times {10^6}\,m$ from the earth surface is
A
$ - 0.5\,mg{R_e}$
B
$ - mg{R_e}$
C
$ - 2\,mg{R_e}$
D
$4\,mg{R_e}$
(AIIMS-2000) (AIIMS-2014)
Solution
(a) Potential energy = $\frac{{ – GMm}}{r} $
$= \frac{{GMm}}{{{R_e} + h}} $
$= \frac{{ – GMm}}{{2{R_e}}}$
$= – \frac{{gR_e^2m}}{{2{R_e}}}$
$= – \frac{1}{2}mg{R_e}$
$ = – 0.5mg{R_e}$
Standard 11
Physics
Similar Questions
normal