Pulling force making an angle theta to the h | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $\uparrow: N+F \sin 	heta=W \Rightarrow N=W-F \sin 	heta$

The block will move if

$F \cos 	heta \geq f_{\max }$

$F \cos 	heta \geq \mu

Vedclass · Accepted Answer

$\frac{{W\sin \alpha }}{{\cos (	heta - \alpha )}}$

Vedclass · Answer

(c) $\uparrow: N+F \sin 	heta=W \Rightarrow N=W-F \sin 	heta$

The block will move if

$F \cos 	heta \geq f_{\max }$

$F \cos 	heta \geq \mu(W-F \sin 	heta)$

$\mu=	an \alpha=\frac{\sin \alpha}{\cos \alpha}$

$F \cos 	heta \geq \frac{\sin \alpha}{\cos \alpha}(W-F \sin 	heta)$

$F(\cos 	heta \cos \alpha+\sin 	heta \sin \alpha) \geq W \sin \alpha$

$F \geq \frac{W \sin \alpha}{\cos (	heta-\alpha)}$

$F_{\min }=\frac{W \sin \alpha}{\cos (	heta-\alpha)}$

Pulling force making an angle $\theta $ to the horizontal is applied on a block of weight $W$ placed on a horizontal table. If the angle of friction is $\alpha $, then the magnitude of force required to move the body is equal to

Similar Questions

Calculate the maximum acceleration (in $m s ^{-2}$) of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is $0.15$ $\left( g =10 m s ^{-2}\right)$.

A block of weight $W$ is kept on a rough horizontal surface (friction coefficient $\mu$). Two forces $W/2$ each are applied as shown in the figure. Choose the $CORRECT$ statement :-

The maximum static frictional force is