3-2.Motion in Plane
medium

મહતમ અવધિ માટે અવધિ અને ઉડ્ડયન સમયના વર્ગનો ગુણોતર

A

$\frac{g}{2}$

B

$\frac{g}{5}$

C

$\frac{g}{10}$

D

$\frac{g}{12}$

(AIIMS-2019)

Solution

The maximum range of projectile motion is given as,

$R=\frac{u^{2} \sin 2 \theta}{g}$

The time of flight of projectile motion is given as,

$T=\frac{2 u \sin \theta}{g}$

The square of time of flight of projectile motion is,

$T^{2}=\left(\frac{2 u \sin \theta}{g}\right)^{2}$

$=\frac{4 u^{2} \sin ^{2} \theta}{g^{2}}$

The ratio of maximum range and square of time of flight in projectile motion is calculated as,

$\frac{R}{T^{2}}=\frac{\frac{u^{2} \sin 2 \theta}{g}}{\frac{4 u^{2} \sin ^{2} \theta}{g^{2}}}$

$=\frac{g}{2} \cot \theta$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.