દર્શાવો કે $a \cdot( b \times c )$ એ ત્રણ સદિશો $a b$ અને $c$ થી બનતા સમાંતરબાજુ ચતુષ્કલકના કર બરાબર હોય છે.

Volume of the given parallelepiped $=a b c$

$\overrightarrow{ OC }=\vec{a}$

$\overrightarrow{ OB }=\vec{b}$

$\overrightarrow{ OC }=\vec{c}$

Let $\hat{ n }$ be a unit vector perpendicular to both $b$ and $c .$ Hence, $\quad \hat{ n }$ and $a$ have the same direction. $\therefore \vec{b} \times \vec{c}=b c \sin \theta \hat{ n }$

$=b c \sin 90^{\circ} \hat{ n }$

$=b c \hat{n}$

$\vec{a} \cdot(\vec{b} \times \vec{c})$

$=a \cdot(b c \hat{ n })$

$=a b c \cos \theta \hat{ n }$

$=a b c \cos 0^{\circ}$

$=a b c$

$=$ Volume of the parallelepiped