Show that the path of a moving point such that its distances from two lines $3 x-2 y=5$ and $3 x+2 y=5$ are equal is a straight line.
Show that the path of a moving point such that its distances from two lines $3 x-2 y=5$ and $3 x+2 y=5$ are equal is a straight line.
Given lines are
${3x - 2y = 5}$......$(1)$
and ${3x + 2y = 5}$.....$(2)$
Let $(h, k)$ is any point, whose distances from the lines $(1) $ and $(2)$ are equal. Therefore
$\frac{{|3h - 2k - 5|}}{{\sqrt {9 + 4} }} = \frac{{|3h + 2k - 5|}}{{\sqrt {9 + 4} }}$
${\text{or }}|3h - 2k - 5| = |3h + 2k - 5|$
${{\text{which gives }}3h - 2k - 5 = 3h + 2k - 5{\text{ or }} - (3h - 2k - 5)}$
${ = 3h + 2k - 5}$
Solving these two relations we get $k=0$ or $h=\frac{5}{3} .$ Thus, the point $(h, k)$ satisfies the equations $y=0$ or $x=\frac{5}{3},$ which represent straight lines. Hence, path of the point equidistant from the lines $(1)$ and $(2)$ is a straight line.
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- [IIT 2000]
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