Let PS be median of triangle with vertices P(2,2) , Q(6,-1) and R(7,3) . equation of line passing th

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9.Straight Line

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Let $PS$ be the median of the triangle with vertices $P(2,2) , Q(6,-1) $ and $R(7,3) $. The equation of the line passing through $(1,-1) $ and parallel to $PS $ is :

A

$4x + 7y + 3 = 0$

B

$\;2x - 9y - 11 = 0$

C

$\;4x - 7y - 11 = 0$

D

$\;2x + 9y + 7 = 0$

(JEE MAIN-2014) (IIT-2000)

Solution

Mld point of $OR$ is $\left(\frac{13}{2}, 1\right)$

Slope of $\mathrm{PS}=\frac{-1}{\frac{9}{2}}=\frac{-2}{9}$

and line passes through $(1,-1)$

$\frac{y+1}{x-1}=\frac{-2}{9}$

$2 x+9 y+7=0$

Standard 11

Mathematics

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