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3 and 4 .Determinants and Matrices
easy
સમીકરણ $\left| {\,\begin{array}{*{20}{c}}1&1&x\\{p + 1}&{p + 1}&{p + x}\\3&{x + 1}&{x + 2}\end{array}\,} \right| = 0$ નો ઉકેલ મેળવો.
A
$x = 1,\,2$
B
$x = 2,\,3$
C
$x = 1,\,p,\,2$
D
$x = 1,\,2,\, - p$
Solution
(a) $A = \left| {\begin{array}{*{20}{c}}1&1&x\\{p + 1}&{p + 1}&{p + x}\\3&{x + 1}&{x + 2}\end{array}\,} \right|$
$|A|\, = 0\,{\rm{for}}\,x = 1\,{\rm{ and }}2$.
So option $(a)$ is correct.
Standard 12
Mathematics