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Basic of Logarithms
normal
Solution set of equation
$\left| {1 - {{\log }_{\frac{1}{6}}}x} \right| + \left| {{{\log }_2}x} \right| + 2 = \left| {3 - {{\log }_{\frac{1}{6}}}x + {{\log }_{\frac{1}{2}}}x} \right|$ is $\left[ {\frac{a}{b},a} \right],a,b, \in N,$ then the value of $(a + b)$ is
A
$5$
B
$6$
C
$7$
D
$8$
Solution
$|a+b+c|=|a|+|b|+|c|$
when $a, b, c$ has same sign.
Standard 11
Mathematics
