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5. Continuity and Differentiation
normal
Suppose that $f (0) = - 3$ and $f ' (x) \le 5$ for all values of $x$. Then the largest value which $f (2)$ can attain is
A
$7$
B
$- 7$
C
$13$
D
$8$
Solution
Using $LMVT$ in $[0, 2]$
$\frac{{f(2) – f(0)}}{{2 – 0}}= f ' (c) $ where $c \in (0, 2)$
$\frac{{f(2) + 3}}{2} \le 5$
$,f (2) \le 7 ==> ( A)$
Standard 12
Mathematics