Gujarati
Hindi
5. Continuity and Differentiation
normal

Suppose that $f (0) = - 3$ and $f ' (x) \le 5$ for all values of $x$. Then the largest value which $f (2)$ can attain is

A

$7$

B

$- 7$

C

$13$

D

$8$

Solution

Using $LMVT$ in $[0, 2]$

$\frac{{f(2) – f(0)}}{{2 – 0}}= f ' (c) $ where $c \in (0, 2)$

$\frac{{f(2) + 3}}{2} \le 5$

$,f (2) \le 7 ==> ( A)$

Standard 12
Mathematics

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