Let $f(x) = (x-4)(x-5)(x-6)(x-7)$ then -
Let $f(x) = (x-4)(x-5)(x-6)(x-7)$ then -
- A
$f'(x) = 0$ has four roots
- B
Three roots of $f'(x) = 0$ lie in $(4, 5) \cup (5, 6) \cup (6, 7)$
- C
The equation $f'(x) = 0$ has only one root
- D
Three roots of $f'(x) = 0$ lie in $(3, 4) \cup (4, 5) \cup (5, 6)$
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