The solubility of a salt of weak acid ( A B ) | vedclass

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Question

Solubility $=\sqrt{ K _{ sp }\left(1+\frac{\left[ n ^{+}ight]}{ Ka }ight)}$

$Y 	imes 10^{-3}  =\sqrt{2 	imes 10^{-10}\left(1+\frac{10^{-

Vedclass · Accepted Answer

$4.47$

Vedclass · Answer

Solubility $=\sqrt{ K _{ sp }\left(1+\frac{\left[ n ^{+}ight]}{ Ka }ight)}$

$Y 	imes 10^{-3}  =\sqrt{2 	imes 10^{-10}\left(1+\frac{10^{-3}}{10^{-8}}ight)}=\sqrt{2 	imes 10^{-5}}$

$Y 	imes 10^{-3}  =\sqrt{20 	imes 10^{-6}}=\sqrt{20} 	imes 10^{-3}$

$Y  =\sqrt{20}=4.47$

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