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6-2.Equilibrium-II (Ionic Equilibrium)
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$0.1\, M$ एसीटिक अम्ल का $pH$ निम्नांकित में से किसके नजदीक है
[अम्ल का वियोजन नियतांक, $K _{ a }=1.8 \times 10^{-5}$ ]
A$2.87$
B$1.00$
C$2.07$
D$4.76$
(KVPY-2017)
Solution
(a)
Given,
dissociation constant, $K_{a}=18 \times 10^{-5}$
Concentration of $\left[ H ^{+}\right]=0.1\, M$
For dissociation of acetic acid
$CH _{3} COOH \rightleftharpoons CH _{3} COO ^{-}+ H ^{+}$
$H ^{+} =\sqrt{k_{a} c}$
$=\sqrt{18 \times 10^{-5} \times 0.1}$
$=\sqrt{18} \times 10^{-3}$
$=1.34 \times 10^{-3}$
$pH =-\log \left[ H ^{+}\right]$
$=-\log \left(1.34 \times 10^{-3}\right)$
$=3-\log 1.34$
$=2.87$
Given,
dissociation constant, $K_{a}=18 \times 10^{-5}$
Concentration of $\left[ H ^{+}\right]=0.1\, M$
For dissociation of acetic acid
$CH _{3} COOH \rightleftharpoons CH _{3} COO ^{-}+ H ^{+}$
$H ^{+} =\sqrt{k_{a} c}$
$=\sqrt{18 \times 10^{-5} \times 0.1}$
$=\sqrt{18} \times 10^{-3}$
$=1.34 \times 10^{-3}$
$pH =-\log \left[ H ^{+}\right]$
$=-\log \left(1.34 \times 10^{-3}\right)$
$=3-\log 1.34$
$=2.87$
Standard 11
Chemistry
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