2.Motion in Straight Line
medium

એક પદાર્થનો વેગ વિરુધ્ધ સમયનો આલેખ આપેલ છે.તો તેના માટે મહત્તમ પ્રવેગ કેટલા.......$\mathrm{cm/sec}^{2}$ મળે?

A

$1$

B

$2$

C

$3$

D

$6$

Solution

(d) Maximum acceleration means maximum change in velocity in minimum time interval.

In time interval $t = 30$ to $t = 40\,sec $

$a = \frac{{\Delta v}}{{\Delta t}} = \frac{{80 – 20}}{{40 – 30}} = \frac{{60}}{{10}} = 6\;cm/{\sec ^2}$

Standard 11
Physics

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