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6-2.Equilibrium-II (Ionic Equilibrium)
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The $pH$ of a $0.1\ M$ aqueous solution of a very weak acid $(HA)$ is $3$. What is its degree of dissociation ?......$\%$
A
$1$
B
$10$
C
$25$
D
None of these
Solution
Given:-
$\mathrm{pH}=3$
Concentration $\longrightarrow 0.1 \mathrm{M}$
Weak acid $\longrightarrow$ HA
$\mathrm{HA} \rightleftharpoons \mathrm{H}^{\oplus}+\mathrm{A}^{\ominus}$
$\mathrm{C} \quad 0 \quad 0$
$\mathrm{C}(1-\alpha) \quad \mathrm{C} \alpha \quad \mathrm{C} \alpha$
$\left[\mathrm{H}^{+}\right]=\mathrm{C} \alpha$
$\Rightarrow-\log \left[\mathrm{H}^{+}\right]=3$
$\Rightarrow\left[\mathrm{H}^{+}\right]=10^{-3}$
$\Rightarrow 10^{-3}=0.1 \times \alpha$
$\Rightarrow \alpha=10^{-2}$
$\Rightarrow \alpha=1 \%$
Standard 11
Chemistry
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