The acceleration due to gravity at a place is ${\pi ^2}\,m/se{c^2}$. Then the time period of a simple pendulum of length one metre is
$\frac{2}{\pi }\,sec$
$2\pi \,sec$
$2\,sec$
$\pi \,sec$
Length of a simple pendulum is $l$ and its maximum angular displacement is $\theta$, then its maximum $K.E.$ is
Two simple pendulums of length $1\, m$ and $4\, m$ respectively are both given small displacement in the same direction at the same instant. They will be again in phase after the shorter pendulum has completed number of oscillations equal to
What is the length of a simple pendulum, which ticks seconds?
If the length of a pendulum is made $9$ times and mass of the bob is made $4$ times then the value of time period becomes
There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is $T$. If the resultant acceleration becomes $g/4,$ then the new time period of the pendulum is