The acceleration time graph of a particle moving along a straight line is shown. At what time particle acquires its initial velocity........$s$
$12$
$5$
$8$
$16$
Given figure shows the $x-t$ plot of one-dimensional motion of a particle. Is it correct to say from the graph that the particle moves in a straight line for $t < 0$ and on a parabolic path for $t >0$? If not, suggest a suitable physical context for this graph.
Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
Colum $I$ | Colum $II$ |
$(A)$ Velocity-time graph | $(p)$ Slope $\rightarrow$ negative |
$(B)$ Acceleration-time graph | $(q)$ Slope $\rightarrow$ positive |
$(C)$ Displacement-time graph | $(r)$ Slope $\rightarrow$ zero |
$(s)$ $\mid$ Slope $\mid \rightarrow$ increasing | |
$(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing | |
$(u)$ |Slope| $\rightarrow$ constant |
The acceleration of a particle is increasing linearly with time $t$ as $bt$. The particle starts from the origin with an initial velocity ${v_0}$. The distance travelled by the particle in time $t$ will be
The initial velocity of a particle is $u\left(\right.$ at $t=0$ ) and the acceleration a is given by $\alpha t^{3 / 2}$. Which of the following relations is valid?
A Body moves $6\, m$ north. $8 \,m$ east and $10\;m$ vertically upwards, what is its resultant displacement from initial position