The activity of a radioactive sample falls fr | vedclass

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Question

$A=A_{0}\left(\frac{1}{2}\right) \frac{t}{T_{1 / 2}}$

$500=700\left(\frac{1}{2}\right) \frac{t}{T_{1 / 2}}$

$0.7 \approx\left(\frac{1}{2}\right)

Vedclass · Accepted Answer

$62$

Vedclass · Answer

$A=A_{0}\left(\frac{1}{2}\right) \frac{t}{T_{1 / 2}}$

$500=700\left(\frac{1}{2}\right) \frac{t}{T_{1 / 2}}$

$0.7 \approx\left(\frac{1}{2}\right) \frac{t}{T_{1 / 2}}$

$\left(\frac{1}{2}\right)^{1 / 2} \approx \frac{t}{T_{1 / 2}}$

$\frac{30}{\mathrm{T}_{1 / 2}} \approx \frac{1}{2} \Rightarrow \mathrm{T}_{1 / 2}=60$

The activity of a radioactive sample falls from $700 \;\mathrm{s}^{-1}$ to $500\; \mathrm{s}^{-1}$ in $30\;min$. Its half life is close to.........$min$

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