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8.Mechanical Properties of Solids
medium
The adjacent graph shows the extension $(\Delta l)$ of a wire of length $1m$ suspended from the top of a roof at one end with a load $W$ connected to the other end. If the cross sectional area of the wire is ${10^{ - 6}}{m^2},$ calculate the young’s modulus of the material of the wire
A
$2 \times {10^{11\,}}N/{m^2}$
B
$2 \times {10^{ - 11}}N/{m^2}$
C
$3 \times {10^{ - 12}}N/{m^2}$
D
$2 \times {10^{ - 13}}N/{m^2}$
(IIT-2003)
Solution
(a)From the graph $l = {10^{ – 4}}m,\;F = 20N$
$A = {10^{ – 6}}{m^2},\;L = 1m$
$Y = \frac{{FL}}{{Al}}$$ = \frac{{20 \times 1}}{{{{10}^{ – 6}} \times {{10}^{ – 4}}}} = 20 \times {10^{10}} = 2 \times {10^{11}}N/{m^2}$
Standard 11
Physics
