The angle made by the vector A = hat i + hat | vedclass

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Question

(b) $\vec A = \hat i + \hat j$ 
$&rArr;$ $|A| = \sqrt {{1^2} + {1^2}} = \sqrt 2 $
$\cos \alpha = \frac{{{A_x}}}{{|A|}} = \frac{1}{{\sqrt 2 }} =

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(b) $\vec A = \hat i + \hat j$ 
$&rArr;$ $|A| = \sqrt {{1^2} + {1^2}} = \sqrt 2 $
$\cos \alpha = \frac{{{A_x}}}{{|A|}} = \frac{1}{{\sqrt 2 }} = \cos 45^\circ $ 
$&rArr;$ $\alpha = 45^\circ $

The angle made by the vector $A = \hat i + \hat j$ with $x-$ axis is ....... $^o$

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