The angular momentum of a particle performing uniform circular motion is $L$. If the kinetic energy of partical is doubled and frequency is halved, then angular momentum becomes
The angular momentum of a particle performing uniform circular motion is $L$. If the kinetic energy of partical is doubled and frequency is halved, then angular momentum becomes
- A
$\frac{L}{2}$
- B
$2 L$
- C
$\frac{L}{4}$
- D
$4 L$
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