The area of a triangle is $5$ and two of its vertices are $A(2, 1), B(3, -2)$. The third vertex which lies on line $y = x + 3$ is-
The area of a triangle is $5$ and two of its vertices are $A(2, 1), B(3, -2)$. The third vertex which lies on line $y = x + 3$ is-
- A
$\left( {\frac{7}{2},\frac{{13}}{2}} \right)$
- B
$\left( {\frac{5}{2},\frac{{11}}{2}} \right)$
- C
$-\left( {\frac{3}{2},\frac{{3}}{2}} \right)$
- D
$(0, 0)$
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