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The centres of two circles $C_1$ and $C_2$ each of unit radius are at a distance of $6$ units from each other. Let $P$ be the mid point of the line segment joining the centres of $C_1$ and $C_2$ and $C$ be a circle touching circles $C_1$ and $C_2$ externally. If a common tangent to $C_1$ and $C$ passing through $P$ is also a common tangent to $C_2$ and $C$, then the radius of the circle $C$ is
$3$
$4$
$6$
$8$
Solution

Let $A_1, A_2$ and $M$ be the centres of the circles $C_1, C_2$ and $C$ respectively. Let the common tangent through P to $C _1$ and C touch $C _1$ at $B _1$ and C at $B _2$ and it touches $C _2$ also at $B _2$
From right angled triangle $A _1 B_2, P$
$\text { if } \underline{ A _1 PB_2}=\alpha, \frac{ A _1 B_2}{A_1 P }=\frac{1}{3}$
$\Rightarrow \cos \alpha=\frac{2 \sqrt{2}}{3} \Rightarrow PB _1=2 \sqrt{2}= PB _2$
From triangle $MPB _2$
$\tan \alpha=\frac{ PB _2}{ MB _2}=\frac{2 \sqrt{2}}{ r }$
$\Rightarrow \frac{1}{2 \sqrt{2}}=\frac{2 \sqrt{2}}{ r }$
$\Rightarrow r =8$