The figure shows some of the electric field lines corresponding to an electric field. The figure suggests

A square surface of side $L$ metres is in the plane of the paper. A uniform electric field $\vec E(V/m) $, also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI units associated with the surface is

The electric field intensity at $P$ and $Q$, in the shown arrangement, are in the ratio

If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface, then:

Two surfaces $S_1$ and $S_2$ are shown in figure. Flux associated with $S_1$ is ${\phi _1}$ and $S_2$ is ${\phi _2}$. Which is correct ?