7.Binomial Theorem
normal

$(x-1) (x- 2) (x-3)...............(x-10)$ ના વિસ્તરણમાં $x^8$ નો સહગુણક મેળવો 

A

$2640$

B

$1320$

C

$1370$

D

$2740$

Solution

Coeff of $x^{8}$

$=\frac{(1+2+3+\ldots .10)^{2}-\left(1^{2}+2^{2}+\ldots .10^{2}\right)}{2}$

$=1320$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.