10-2.Transmission of Heat
medium

કોપરની ઉષ્મા વાહકતા સ્ટીલ કરતાં $ 9$ ગણી હોય તો સંપર્ક સપાટીનું તાપમાન ......... $^oC$

A

$ 75$

B

$67$

C

$33$

D

$25$

Solution

(a) Temperature of interface $\theta = \frac{{{K_1}{\theta _1}{l_2} + {K_2}{\theta _2}{l_1}}}{{{K_1}{l_2} + {K_2}{l_1}}}$

It is given that ${K_{Cu}} = 9{K_S}.$ So if ${K_S} = {K_1} = K$ then ${K_{Cu}} = {K_2} = 9K$

==> $\theta  = \frac{{9K \times 100 \times 6 + K \times 0 \times 18}}{{9K \times 6 + K \times 18}}$=$\frac{{5400K}}{{72K}} = 75^\circ C$

Standard 11
Physics

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