Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

The coefficient of volumetric expansion of mercury is $18 × 10^{-5}{°C^{-1}}$. A thermometer bulb has a volume $10^{-6}\, m^3$ and cross section of stem is $ 0.004 \,cm^2$. Assuming that bulb is filled with mercury at $0°C$ then the length of the mercury column at $100°C$ is

A

$18.8 \,mm$

B

$9.2\, mm$

C

$7.4\, cm$

D

$4.5\, cm$

Solution

(d) $V = V_0(1 + \gamma \Delta \theta)$ $⇒$ Change in volume

$V – {V_0} = \Delta V = A.\Delta l = {V_0}\gamma \Delta \theta $

$⇒$ $\Delta l = \frac{{{V_0}.\Delta \theta }}{A}$ = $\frac{{{{10}^{ – 6}} \times 18 \times {{10}^{ – 5}} \times (100 – 0)}}{{0.004 \times {{10}^{ – 4}}}}$

= $45 × 10^{-3} m = 4.5 cm$

Standard 11
Physics

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